What has to happen before a bottle can become a bottle?
A transparent drinks bottle, a water-absorbing dressing and a nylon thread serve very different purposes, yet their manufacture begins with a common question: which small molecules should be prepared so that they can be connected into the required long chains? Poly(ethylene terephthalate), widely used in bottles, requires a diacid and a diol that can react with one another. A polyacrylamide gel develops its backbone from the carbon–carbon double bonds of acrylamide. A nylon can be assembled by joining molecules carrying amine groups with molecules carrying carboxyl groups. Preparation before polymerization determines the available backbone, side groups and connections, as well as the impurities that later operations must handle.
“Small” here means small relative to a polymer. A monomer is a molecule that can contribute structural units through a polymerization reaction; it is not simply any low-mass molecule. Water molecules are small, but collecting them does not ordinarily produce a polymer. A cyclic monomer can open its ring and enter a chain without possessing a carbon–carbon double bond. When examining a monomer, start with two questions: where can it connect, and which parts of the molecule remain in the resulting material? These questions turn a structural formula into a description of possibilities, instead of another abbreviation to memorize.
The letters in a chemical formula identify elements: C denotes carbon, H hydrogen, O oxygen, N nitrogen and Cl chlorine. A subscript specifies how many atoms of an element occur in the molecule. Lines between atoms represent chemical bonds, with two lines for a double bond and three for a triple bond. Ethylene, CH₂=CH₂, contains two carbon atoms joined by a double bond, each also attached to two hydrogens. During addition polymerization, part of that bonding capacity is used to connect neighbouring monomers; the carbon atoms remain. A carboxyl group, —COOH, a hydroxyl group, —OH, and an amino group, —NH₂, provide other common reaction sites, collectively called functional groups.
Building blocks with connectors offer a useful analogy, although molecular connectors have orientation, reaction rates and preferences. Some react readily with water, some need a catalyst to become accessible, and some can begin joining during storage. Industrial monomer preparation therefore involves more than making a named molecule. It must separate that molecule from similar compounds, control water, residual catalysts and trace components that affect polymerization, and deliver it in a condition suitable for storage and use. The origin of a material's eventual performance often lies well upstream of the polymerization vessel.
Separating a feedstock and changing a molecule
Separating crude oil into fractions primarily exploits differences in volatility. On heating a mixture, the components that enter the vapour more readily become enriched there. Repeated contact between vapour and liquid in a column progressively improves separation. Naphtha obtained this way remains a mixture of hydrocarbons, compounds consisting mainly of carbon and hydrogen. Distillation changes the composition collected at different locations; merely putting fractions in separate containers does not broadly convert their carbon skeletons into ethylene. Cracking performs the subsequent chemical transformation, producing smaller molecules that are useful starting points for monomers.
Feeds can also be obtained by separating ethane, propane and other components from natural-gas streams. Ethane contains two carbons, so its simplest overall conversion to ethylene removes one hydrogen molecule. Naphtha contains a wider range of carbon structures, and cracking it produces a mixture including ethylene, propylene, four-carbon components and heavier liquids. Different feeds therefore create different product portfolios. A plant must arrange destinations for all these streams. The practicality of a route depends on the desired monomer together with the handling and value of hydrogen, fuel gas and other co-products generated alongside it.
Elements beyond the carbon skeleton come from additional industries. Chlorine and caustic soda from brine electrolysis, ammonia made using nitrogen from air, oxygen for oxidation and hydrogen for hydrogenation all enter monomer networks. In brine electrolysis, electrical energy drives chloride ions toward chlorine formation at the anode, while hydrogen and hydroxide are generated on the cathode side. A suitable diaphragm or membrane keeps the products apart so that they do not immediately react again. An electrode is an interface through which electric current enters or leaves the liquid; an ion is an electrically charged atom or group of atoms. These basic roles explain why organic materials depend on inorganic chemical manufacturing.
| Symbol | Meaning | Unit |
|---|---|---|
| NaCl | Sodium chloride; Na denotes sodium and Cl chlorine | chemical formula |
| H₂O | Water; H denotes hydrogen and O oxygen | chemical formula |
| NaOH | Sodium hydroxide | chemical formula |
| Cl₂, H₂ | Chlorine and hydrogen gases, each with two atoms per molecule | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipTwo salt units supply two sodium and two chlorine atoms; water supplies hydrogen and oxygen. Each element has the same total atom count on both sides. Electrical energy drives the electrochemical transformation.
A worked exampleOn the net-reaction basis, conversion of 2 kmol NaCl gives 2 kmol NaOH, 1 kmol Cl₂ and 1 kmol H₂, consuming 2 kmol water.
ConditionsThis is net chlor-alkali stoichiometry. Electrical demand, current efficiency, water transport and product concentration depend on the electrolysis system.
Other routes begin with mixtures of carbon monoxide and hydrogen and enter the organic-chemical network through intermediates such as methanol. Acetylene can be made from different feedstocks and used in some routes to chlorine- or oxygen-containing monomers. Biomass can first be fermented to ethanol, which can then lose water to produce ethylene. These routes supply atoms and energy in different ways. If they ultimately deliver ethylene of the same molecular structure and purity, polymerization encounters the same molecule. A meaningful comparison follows feed preparation, reaction, separation and energy supply together, rather than assigning a whole process an environmental character from the name of its starting material.
Another useful habit is to inspect each arrow in a route diagram. Does the carbon count change? Which functional group is modified? Must another feed contribute atoms? An arrow from ethylene toward a polyester generally represents several steps through ethylene oxide and ethylene glycol, followed by reaction with a separately supplied diacid. It does not mean that ethylene alone becomes that polyester. A multistep arrow describes a process connection; a balanced equation describes the atom balance of an individual transformation. Keeping these levels distinct makes even a complicated product tree easier to read.
Why a cracking furnace needs rapid heating and rapid cooling
The overall ethane reaction provides a starting point for thermal cracking. Removing two hydrogen atoms produces ethylene, while those hydrogens form hydrogen gas. This net change absorbs heat, so the furnace must continuously supply energy to the flowing gas. Actual molecules do not complete a single orderly step, however. At elevated temperatures, some bonds break homolytically: the two electrons previously shared in a bond separate between the fragments, generating radicals with unpaired electrons. A radical can abstract hydrogen from another molecule; the new radical can fragment or transfer activity again. The result is a connected network of reactions rather than one isolated conversion.
| Symbol | Meaning | Unit |
|---|---|---|
| C₂H₆ | Ethane, with two carbons and six hydrogens | chemical formula |
| C₂H₄ | Ethylene, with two carbons and four hydrogens | chemical formula |
| H₂ | Hydrogen molecule | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipThe carbon skeleton remains, while the two removed hydrogens form one hydrogen molecule. One gaseous reactant molecule gives two gaseous product molecules, increasing total molecular count.
A worked exampleIn the ideal desired reaction, 1 kmol ethane produces 1 kmol ethylene and 1 kmol hydrogen. Rounded molar masses give 30 kg = 28 kg + 2 kg.
ConditionsStoichiometry of the desired reaction. Thermal cracking also forms other products through radical steps; the overall equation does not specify a single-step mechanism.
In 1931, F. O. Rice discussed the thermal decomposition of saturated hydrocarbons in terms of free-radical reactions. This framework connected complex products to specific bond cleavage, hydrogen abstraction and propagation steps, going beyond a list of substances found after heating. A “chain reaction” in this context means that reactive intermediates pass activity onward. It need not produce a long polymer molecule. Reaction chains in a cracking furnace can generate small molecules, whereas chain-growth polymerization adds monomers to an increasingly large molecule. Both involve successive reaction steps, but molecular size changes in different directions. Rice's study of radical thermal decomposition provides a historical bridge between observed products and molecular mechanisms.
Raising temperature accelerates the desired chemistry and many competing reactions. Newly formed ethylene can undergo further reactions if it remains hot, while heavier components can form aromatic products and coke. Coke deposited on a tube wall impedes heat transfer, reduces the flow passage and changes pressure loss. Cracking therefore often combines high temperature with a relatively short high-temperature history: the desired reaction proceeds during a favourable window, after which cooling reduces further transformation of the products. Quickly cooling food after blanching likewise shortens its subsequent thermal history. The chemistry and temperature scales differ, but the useful analogy is that ending the exposure at the right time matters as much as starting it.
Dilution steam commonly enters the cracking section with the hydrocarbon. It reduces hydrocarbon partial pressure, changes molecular encounter frequencies and influences coke formation and flow. Partial pressure is the portion of a gas mixture's pressure associated with one component: at a fixed total pressure, adding a larger steam fraction reduces the hydrocarbon fraction. Steam is not the oxygen supplied for complete combustion, and increasing it indefinitely is not cost-free. More steam requires more material to be heated and subsequently separated. It also increases volumetric flow, changing velocity and residence time in the tubes. Its chemical effects and equipment demands belong in the same assessment.
Hot gas leaving the cracking tubes can first pass through a transfer-line exchanger, delivering heat to water on the other side and generating steam. Further oil quenching, water cooling or other suitable cooling and separation stages follow according to the stream. The exchanger rapidly removes heat while recovering high-temperature energy; it is not simply a spray condenser that instantly liquefies all the cracked gas. Light products still require compression, removal of acidic contaminants, drying and separation. Closely related small molecules can demand substantial purification before meeting polymerization requirements. The furnace determines which substances are generated, while the separation train determines what can be delivered as a monomer product.
From one tonne of ethylene per hour to heat and flow
A continuous worked example connects the reaction equation to equipment scale. Suppose the desired ethylene output is 1000 kg per hour. Using a rounded molar mass of 28 kg per kmol gives approximately 35.71 kmol per hour. The mole is a unit that counts particles, and one kilomole contains 1000 moles; molar mass connects that particle count with mass. The statement “one ethane gives one ethylene” refers to molecule numbers or molar amounts, not equal masses. Some mass from ethane leaves as hydrogen, so both products must be included in a mass balance.
| Symbol | Meaning | Unit |
|---|---|---|
| ṁ_E | Ethylene product mass flow; a dot denotes amount per time | kg h⁻¹ |
| ME | Ethylene molar mass, rounded here to 28 | kg kmol⁻¹ |
| ṅ_E | Ethylene product molar flow | kmol h⁻¹ |
| ṅ_A,0 | Reaction-section ethane inlet molar flow; A denotes ethane and 0 the inlet | kmol h⁻¹ |
| X | Single-pass ethane conversion as a fraction | 1 |
| ṅ_W,0 | Reaction-section steam inlet molar flow | kmol h⁻¹ |
| S | Inlet steam-to-ethane molar ratio | 1 |
Reading the relationshipMass divided by molar mass gives molar amount. One converted ethane gives one ethylene, so output divided by conversion gives section inlet flow; the steam ratio then supplies the water flow.
A worked example1000 kg/h divided by 28 kg/kmol gives 35.714 kmol/h. At X=0.30 ethane feed is 119.048 kmol/h; at S=1.5 steam is 178.571 kmol/h.
Conditions100% selectivity to the desired reaction, complete product recovery and no ethylene in the feed. Ethane flow is total reaction-section feed, including any recycle.
Take a single-pass ethane conversion of 30% and, for this balance, a selectivity of 100% to the desired reaction. The required ethane flow into the reaction section is then about 119.05 kmol per hour, of which 83.33 kmol per hour remains unconverted. Separated ethane can be recycled, so the reaction-section feed and the fresh ethane supplied to the whole plant are different quantities. At an ideal steady state with complete recovery and no loss, fresh feed replaces only the net amount consumed. Side reactions, purge streams and separation losses increase that requirement in an actual process. Conversion and selectivity are therefore needed together to describe raw-material use.
For the heat balance, place the boundary around a section whose inlet and outlet streams are gaseous. Set inlet and outlet temperatures to 800 K and 1000 K. Use representative mean molar heat capacities of 115 kJ/(kmol·K) for ethane and 40 kJ/(kmol·K) for steam, together with a reaction heat absorption of 150000 kJ per kmol at the outlet temperature. These are rounded parameters for the example. Heat capacities vary with temperature, and a more detailed calculation integrates property data over the relevant interval. A convenient hypothetical path first heats all the feed to the outlet temperature and then carries out the required reaction there. Enthalpy is a state function, so this path gives the same total enthalpy change when its starting and ending states match the actual process.
| Symbol | Meaning | Unit |
|---|---|---|
| Q, Qr, Qs | Total duty, reaction heat absorption and sensible-heating rate | kJ h⁻¹ |
| ṅ_E, ṅ_A,0 | Ethylene output and ethane inlet molar flows | kmol h⁻¹ |
| ΔHr(To) | Reaction enthalpy per kmol of desired reaction at outlet temperature; positive for heat absorption | kJ kmol⁻¹ |
| c̄_p,A, c̄_p,W | Mean constant-pressure molar heat capacities of ethane and steam over the heating interval; bar denotes average | kJ kmol⁻¹ K⁻¹ |
| S | Inlet steam/ethane molar ratio | 1 |
| To, Ti, ΔT | Outlet and inlet temperatures and their difference; o denotes outlet and i inlet | K |
Reading the relationshipUse an enthalpy path that heats all feed first and reacts it at outlet temperature. Reactions per hour times heat absorbed per reaction, plus feed heat-capacity flow times temperature rise, gives stream duty.
A worked exampleAt X=0.30, S=1.5, a 200 K rise, heat capacities 115 and 40, and reaction enthalpy 150000: Q_r=5357143 kJ/h and Q_s=4166667 kJ/h, totalling 9523810 kJ/h. Dividing by 3600 s/h gives 2645.50 kW.
ConditionsSteady gaseous desired reaction with the stated mean heat capacities and reaction enthalpy. Heat loss, shaft work and kinetic/potential changes are neglected within this boundary. Water enters as steam; upstream vaporization is outside it.
With a steam-to-ethane molar ratio of 1.5, the steam feed is approximately 178.57 kmol per hour. The desired reaction absorbs about 1488.10 kW, and heating the feed requires about 1157.41 kW, giving 2645.50 kW in total. Product heating from inlet to outlet must not be added a second time: the reaction enthalpy at the outlet temperature already connects the heated reactants to the products at that temperature. Adding another full product sensible-heat term would double-count part of the change. Upstream steam generation, heat loss through furnace walls and combustion efficiency can be included when the boundary is expanded. Defining the boundary gives the calculated number its meaning.
Next estimate volumetric gas flow. When one ethane molecule becomes an ethylene molecule and a hydrogen molecule, the total number of gas molecules increases by one. Inlet molar flow therefore cannot represent the whole reaction section without an expansion correction. Taking the average of inlet and outlet total molar flows, a representative temperature of 900 K and a pressure of 200 kPa gives about 3.28 cubic metres per second. A representative residence time of 0.30 seconds then corresponds to roughly 0.98 cubic metres. A detailed calculation follows temperature, pressure, composition and velocity along the tube; this midpoint estimate connects heat, flow and dimensions at a common scale.
| Symbol | Meaning | Unit |
|---|---|---|
| ṅ_g,i, ṅ_g,o, ṅ̄_g | Total inlet, outlet and arithmetic-mean gas molar flows; convert to per-second values before calculating q | kmol s⁻¹ |
| ṅ_A,0, ṅ_E | Ethane inlet and ethylene product molar flows, likewise converted to per-second values | kmol s⁻¹ |
| S | Inlet steam/ethane molar ratio | 1 |
| R | Ideal-gas constant, using8.314 | kPa m³ kmol⁻¹ K⁻¹ |
| T̄, P | Representative gas absolute temperature and pressure | K; kPa |
| qeff | Representative volumetric flow | m³ s⁻¹ |
| V, τ | Reaction-section volume and representative residence time | m³; s |
| ≈ | Approximation using representative midpoint conditions | 1 |
Reading the relationshipEach desired reaction increases the total gas amount by one molar unit. The ideal-gas relation converts molar flow to volume flow, and multiplying by time estimates the required volume.
A worked exampleDefault inlet and outlet totals are 297.619 and 333.333 kmol/h. Their mean divided by 3600 is 0.087632 kmol/s. At 900 K and 200 kPa, q is approximately 3.279 m³/s; multiplying by 0.30 s gives V≈0.984 m³.
ConditionsIdeal gas and only the stated reaction. The volume estimate uses representative temperature, pressure and midpoint molar flow. A nonuniform passage requires residence time from the local velocity profile along the flow path.
An average effective heat flux of 75 kW per square metre requires approximately 35.27 square metres of heat-transfer area for the calculated duty. If the passage is temporarily represented by one circular tube, its lateral area and internal volume imply an internal diameter of about 0.112 metres and a length of about 100.7 metres. The two requirements do different jobs: the gas needs enough space for its thermal history, while the wall needs enough area to deliver the energy. Together they determine a geometric scale. A furnace design then also addresses varying heat flux, tube-metal temperature, pressure loss, coke formation and distribution between parallel tubes.
| Symbol | Meaning | Unit |
|---|---|---|
| A | Effective inner lateral heat-transfer area of the model tube | m² |
| Q | Heat duty to the gas, converted here to kilowatts | kW |
| q'' | Mean heat flux on the same area basis; double prime denotes heat per area per time | kW m⁻² |
| V | Internal volume occupied by gas | m³ |
| d, L | Internal tube diameter and total length | m |
| π | Circle constant, approximately3.14159 | 1 |
Reading the relationshipDuty divided by heat delivered per area gives area. The ratio of lateral area to volume in a circular tube is 4/d, fixing diameter; area then fixes length.
A worked exampleQ=2645.50 kW and q″=75 kW/m² give A≈35.27 m². With V≈0.984 m³, d≈0.112 m and L≈100.7 m.
ConditionsThe section is represented by one constant-diameter circular tube, neglecting end areas and using representative uniform heat flux. Temperature distributions, pressure loss and parallel-tube arrangements require further coupling.
Keep output fixed; change conversion and steam ratio
Ethylene1000 kg/h with molar mass rounded to28 kg/kmol. Inlet800 K, outlet1000 K, representative temperature900 K and pressure200 kPa. Mean ethane and steam molar heat capacities115 and40 kJ/(kmol·K), outlet reaction enthalpy150000 kJ/kmol, mean heat flux75 kW/m² and time0.30 s. Axes stay fixed. MW denotes megawatts, with1 MW=1000 kW. This compares ideal material and energy balances at specified conversions.
When changing conversion in the interaction, keep ethylene output fixed. Lower conversion sends more ethane through the reaction section repeatedly and carries more steam when the steam-to-ethane ratio is unchanged. Sensible-heat demand and volumetric flow rise, whereas heat absorbed by the fixed amount of desired reaction remains constant. Increasing the steam ratio separately makes the heating and flow cost of dilution visible. Conversion and steam ratio are specified independently in this comparison of material and energy balances. Reaction kinetics, selectivity and coking behaviour subsequently determine which combinations can be achieved in a particular furnace.
The same two carbons can lead to very different materials
Direct polymerization of ethylene produces polyethylene. Introducing suitable comonomers changes branching, flexibility and interactions with other substances. Ethylene copolymerization with an appropriate alpha-olefin, for example, leaves some carbon segments as side branches and changes chain packing and crystallization. Copolymerization with vinyl acetate introduces oxygen-containing side groups. Copolymerization means that two or more monomers contribute to the chain, and properties depend on their proportions, sequence distribution and polymerization method. A branch in a feedstock tree becomes an explanation of material behaviour only when it is connected to these structural changes.
Another branch first converts ethylene to ethylene oxide, a small ring containing two carbons and one oxygen. Opening this ring allows it to enter a poly(ethylene oxide) chain. The common names PEG and PEO describe the same backbone repeat structure; naming conventions differ with molecular mass and application. Reaction of ethylene oxide with water instead produces ethylene glycol, which has a hydroxyl group at each end. Ethylene glycol can react with terephthalic acid to form PET, with the second feed supplying an aromatic ring and carboxyl groups. The carbon originally present in ethylene can thus enter a flexible, water-affine polyether or a polyester with different stiffness and crystallization behaviour.
Vinyl acetate provides a helpful example of why a polymer name does not always reveal a direct monomer route. Ethylene, acetic acid and oxygen can produce vinyl acetate, which polymerizes into poly(vinyl acetate). Conversion of the polymer's side groups then gives the widely used poly(vinyl alcohol). That final name describes the repeat unit; it does not imply an industrial sequence that stores large quantities of stable vinyl alcohol and directly polymerizes it. Vinyl alcohol readily undergoes tautomerization toward the more stable acetaldehyde form. Polymerizing a suitable precursor and subsequently transforming its side groups is therefore an important route-design strategy.
| Symbol | Meaning | Unit |
|---|---|---|
| C₂H₄ | Ethylene | chemical formula |
| CH₃COOH | Acetic acid, containing a COOH carboxyl group | chemical formula |
| O₂, H₂O | Oxygen and water;1/2 indicates a half molar proportion | chemical formula |
| CH₃COOCH=CH₂ | Vinyl acetate, retaining a carbon–carbon double bond and containing an ester linkage | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipEthylene and acetic acid together supply four carbons. Oxygen participates in the net oxidation, with some hydrogen and oxygen leaving as water. A polymerizable double bond remains in the product.
A worked exampleThe net reaction combines 1 kmol ethylene,1 kmol acetic acid and 0.5 kmol oxygen to give 1 kmol vinyl acetate and 1 kmol water. Both sides contain 4 carbons,8 hydrogens and 3 oxygens per reaction unit.
ConditionsNet stoichiometry of the desired product; the catalytic process also depends on conversion, selectivity, recycle and separation.
Ethylene can also react with benzene to attach a two-carbon fragment to an aromatic ring, forming ethylbenzene. Dehydrogenation then creates styrene. The aromatic ring, a carbon ring with a particular delocalized electronic structure, remains in the monomer, while the newly created vinyl group provides the site for subsequent polymerization. Styrene can produce polystyrene, copolymerize with butadiene to make styrene–butadiene rubber, or participate in more complex toughened materials. Toughening often requires a soft phase to coexist with a harder matrix in a suitable morphology. The letters in a product name may therefore represent copolymer chemistry, grafting and multiple phases, rather than a single uniformly mixed chain.
| Symbol | Meaning | Unit |
|---|---|---|
| C₆H₆, C₂H₄ | Benzene and ethylene | chemical formula |
| C₆H₅CH₂CH₃ | Ethylbenzene; C₆H₅ represents the phenyl part attached to the side group | chemical formula |
| C₆H₅CH=CH₂ | Styrene, with a double bond in the side group | chemical formula |
| H₂ | Hydrogen | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipThe first step attaches the two-carbon fragment supplied by ethylene to the benzene ring. The second removes one hydrogen molecule from the side group, forming a polymerizable vinyl group.
A worked exampleAn ideal net conversion combines 1 mol benzene and 1 mol ethylene into 1 mol styrene plus 1 mol hydrogen. The first-step product C₈H₁₀ becomes C₈H₈ and H₂ in the second step.
ConditionsThe two steps use their corresponding catalytic and separation conditions; the net balance does not imply they occur automatically under identical conditions or in one apparatus.
PEG segments, polyester backbones and hydrophilic side groups are common in biomaterials. Hydrophilicity indicates favourable interactions with water, while the amount of water absorbed also depends on crosslink density, crystallinity and other components. Incorporation into a polymer changes a monomer's reactivity, mobility and biological interactions. Assessment of a final material also considers residual monomer, additives, molecular mass and the fabricated article. Following monomer routes helps identify which structures can be designed and which components must be removed, then connects that knowledge to a particular use.
Vinyl chloride and the return journey of a by-product
Vinyl chloride, the monomer for poly(vinyl chloride), retains a carbon–carbon double bond and carries one chlorine atom. A set of industrial routes starting from ethylene can be understood through three cooperating reactions. Direct addition of chlorine to ethylene produces 1,2-dichloroethane. Cracking dichloroethane produces vinyl chloride and hydrogen chloride. Another portion of ethylene reacts with hydrogen chloride and oxygen in oxychlorination, replenishing dichloroethane. The easiest way to understand the arrangement is to follow chlorine atoms through it, rather than memorize three separate equipment names.
| Symbol | Meaning | Unit |
|---|---|---|
| C₂H₄, Cl₂ | Ethylene and chlorine | chemical formula |
| C₂H₄Cl₂ | 1,2-Dichloroethane, abbreviated EDC | chemical formula |
| C₂H₃Cl | Vinyl chloride monomer, abbreviated VCM | chemical formula |
| HCl | Hydrogen chloride | chemical formula |
| O₂, H₂O | Oxygen and water | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipDirect chlorination adds two chlorines. Cracking releases one as hydrogen chloride. Oxychlorination uses two hydrogen chlorides to supply two chlorines to ethylene, with oxygen forming water from their hydrogens.
A worked exampleOne first-row and one third-row reaction generate 2 molEDC. Two second-row reactions then give 2 molVCM and 2 molHCl, exactly supplying the HCl required in the third row.
ConditionsIdeal balances of the desired reactions. Unconverted feeds and by-products remain in actual reactors, so recycle ratios also incorporate recovery and purification.
Dichloroethane contains two chlorine atoms. One remains in vinyl chloride after cracking, while the other enters hydrogen chloride. Treating all hydrogen chloride as an outgoing by-product would affect both raw-material use and downstream handling. Oxychlorination gives it another destination: two hydrogen chloride molecules supply two chlorines, oxygen combines with their hydrogens to form water, and ethylene receives the chlorines to become dichloroethane. Each ethylene therefore requires two hydrogen chlorides in this step. Balancing the reaction means counting hydrogen, chlorine and oxygen as well as carbon; otherwise the required recycle ratio can easily be wrong.
If one direct-chlorination reaction and one oxychlorination reaction each produce one dichloroethane, cracking the resulting two dichloroethanes generates two hydrogen chlorides. Those supply exactly the one oxychlorination reaction. Cancelling the shared intermediates from the overall account leaves the net reaction: two ethylenes, one chlorine molecule and half an oxygen molecule give two vinyl chlorides and one water molecule. Cancellation means that an intermediate circulates within the ideal steady-state process. It does not mean that the intermediate is physically absent: it still occupies equipment and requires reactors, heat exchangers, separation capacity and a corresponding internal flow.
| Symbol | Meaning | Unit |
|---|---|---|
| C₂H₄ | Ethylene | chemical formula |
| Cl₂, O₂ | Chlorine and oxygen | chemical formula |
| C₂H₃Cl, H₂O | Vinyl chloride and water | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipAdd two EDC cracking reactions, one direct chlorination and one oxychlorination. Cancel shared EDC and HCl to obtain the net balance across the reaction group.
A worked exampleProducing 2 kmolVCM ideally consumes 2 kmol ethylene,1 kmol chlorine and 0.5 kmol oxygen and generates 1 kmol water. Eight hydrogen atoms and two chlorine atoms per net reaction are conserved.
ConditionsIdeal steady state with matched intermediate reuse. Startup inventory, purges, losses and side reactions enter the complete process balance separately.
These three reactions also have different heat-management tasks. Direct chlorination and oxychlorination release heat that must be removed: liquid-phase chlorination can use boiling EDC, while gas–solid catalytic oxychlorination can recover heat through cooling coils. EDC cracking instead requires furnace heat, followed by product cooling and separation. Feed distillation removes water and light and heavy impurities. Drying reduces corrosion associated with wet chloride-containing streams, while temperature and residence time jointly influence conversion, secondary reactions and coke formation. Equipment arrangements depend on the process, but reaction direction, heat flow and downstream separation must be considered together.
This illustrates why process design considers several reactions together. A by-product from one step can become a feed for another. Recycles also carry impurities, however, and compounds that react poorly or separate poorly can accumulate over repeated circulation. Appropriate purification and purge streams are therefore part of the arrangement. Product finishing remains equally important: light components, heavy components and residual intermediates must be separated according to their properties. The transferable lesson is the continuous connection between balanced reactions, compatible recycle flows and monomer purification. The same reasoning applies to many routes that contain no chlorine.
From nitrile to amide: a protein can help manufacture a monomer
Propylene has one more carbon than ethylene. It can polymerize directly into polypropylene or undergo selective oxidation and ammoxidation to produce oxygen- and nitrogen-containing monomers. Selective oxidation must change the intended site while preserving the carbon–carbon double bond needed for polymerization. Propylene can first become acrolein and then acrylic acid. Reaction of acrylic acid with different alcohols produces different acrylate esters; the length and structure of their side groups subsequently influence polymer softness, glass-transition temperature and adhesion. Methyl methacrylate can likewise be made through isobutylene oxidation followed by esterification. Other industrial routes exist, and feed availability affects the choice.
Ammoxidation brings propylene, ammonia and oxygen together to produce acrylonitrile. A nitrile group is —C≡N, containing a carbon–nitrogen triple bond. Acrylonitrile retains a polymerizable carbon–carbon double bond and can form polyacrylonitrile or enter copolymers such as nitrile rubber. Polyacrylonitrile also serves as a precursor for an important class of carbon fibres. Subsequent thermal treatment drives cyclization, carbonization and other structural changes before a carbon material is obtained. Functional groups installed during monomer manufacture therefore influence polymerization and can also prepare reaction sites for transformations much later in processing.
| Symbol | Meaning | Unit |
|---|---|---|
| C₃H₆ | Propylene | chemical formula |
| NH₃ | Ammonia, supplying nitrogen | chemical formula |
| O₂, H₂O | Oxygen and water | chemical formula |
| CH₂=CHCN | Acrylonitrile; CN is a nitrile group with a carbon–nitrogen triple bond | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipThree carbons remain, nitrogen enters the nitrile, and the remaining hydrogens combine with oxygen to form water. Carbon, hydrogen, nitrogen and oxygen are all balanced.
A worked exampleEach 1 mol propylene ideally consumes 1 mol ammonia and 1.5 mol oxygen, yielding 1 mol acrylonitrile and 3 mol water. Three hydrogens in acrylonitrile plus six in water match the nine entering.
ConditionsNet desired ammoxidation. Catalytic selectivity determines actual feed allocation and by-product composition.
Adding one water molecule to the nitrile group of acrylonitrile produces acrylamide: the nitrile becomes —CONH₂ while the carbon–carbon double bond remains. Preserving that double bond matters because it will be used to make polyacrylamide. A molecule with two potentially reactive sites poses a selectivity problem when only one should change. A catalyst alters the reaction pathway so that the desired transformation proceeds more readily under suitable conditions. Its value often includes reducing competing transformations and the separation work they create, in addition to increasing the rate.
| Symbol | Meaning | Unit |
|---|---|---|
| CH₂=CHCN | Acrylonitrile | chemical formula |
| H₂O | Water participating in hydration | chemical formula |
| CH₂=CHCONH₂ | Acrylamide; CONH₂ is an amide group containing a carbon–oxygen double bond | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipOne water molecule supplies an oxygen and two hydrogens to convert the nitrile into an amide, while the carbon–carbon double bond is retained in the desired reaction.
A worked exampleUsing rounded molar masses,53 kg acrylonitrile plus 18 kg water gives 71 kg acrylamide, the net balance for 1 kmol of desired reaction.
ConditionsDesired hydration. The catalyst system must retain the double bond and limit competing further conversion, such as acid formation; product purification follows its intended use.
In 1982, Asano, Yasuda, Tani and Yamada reported an enzymatic method for producing acrylamide from acrylonitrile. They screened microbial systems for strong activity toward the desired hydration together with little further conversion of the product, demonstrating how biological selectivity could serve monomer manufacture. This research direction subsequently entered industrial production. Nitrile hydratase is a protein catalyst whose active centre can contain iron or cobalt. The protein supplies a specific three-dimensional environment that positions the substrate and water for reaction. The early enzymatic acrylamide study provides a direct historical connection between biological macromolecules and the manufacture of familiar synthetic polymers.
Biocatalysis introduces its own process considerations. The desired step hydrates a nitrile into an amide. If another enzyme, an amidase, continues converting the amide into an acid, the product composition changes. Both desired and competing activities therefore matter. Choosing whole cells, immobilized cells or an enzyme preparation also involves catalyst recovery, transport, retention of activity and product purification. The protein does not need to become part of the polyacrylamide; it catalyses a particular manufacturing step. Distinguishing a biological feedstock, a biological catalyst and a biodegradable final material makes the contribution of biotechnology much clearer.
Four-carbon butadiene demonstrates another route pattern. It can polymerize or copolymerize into rubbers, or undergo addition reactions that extend its carbon skeleton into six-carbon adiponitrile. Hydrogenation then yields hexamethylenediamine, which has an amino group at each end. Combined with adipic acid, which has a carboxyl group at each end, it can form nylon 66. Adipic acid can be prepared through oxidation of cyclohexane-derived cyclohexanol and cyclohexanone intermediates. Routes using nitric-acid oxidation also require management of nitrogen-containing by-products, including nitrous oxide that can form. By-products and treatment needs follow the specific chemistry; they cannot be inferred from the final name “nylon” alone.
| Symbol | Meaning | Unit |
|---|---|---|
| C₄H₆ | 1,3-Butadiene | chemical formula |
| HCN | Hydrogen cyanide, supplying one carbon and one nitrogen per molecule | chemical formula |
| NC(CH₂)₄CN | Adiponitrile: the two terminal nitrile carbons plus four internal carbons give six; a subscript outside parentheses counts repeats | chemical formula |
| H₂ | Hydrogen | chemical formula |
| H₂N(CH₂)₆NH₂ | Hexamethylenediamine, a six-carbon skeleton with terminal amino groups | chemical formula |
| → | Direction of the net reaction; preceding coefficients express molar ratios | 1 |
Reading the relationshipTwo HCN units each add a carbon, converting a four-carbon feed into a six-carbon dinitrile. Hydrogenation converts terminal nitriles into amines while retaining their carbons in the skeleton.
A worked exampleOne mol butadiene plus two mol HCN corresponds to one mol adiponitrile; four mol H₂ then gives one mol diamine. In the second step the hydrogen count rises from 8 to 16, with eight supplied by four hydrogens.
ConditionsNet route to the desired product. Catalysis, isomer selectivity and separation determine the actual yield.
Purity and stoichiometry prepare the way for long chains
Monomer purity is more informative than a single total percentage. Two samples can have the same nominal purity, yet behave differently if one contains mostly water as its impurity and the other contains a substance that terminates chain growth. Water participates in some ring-opening and condensation processes, oxygen changes the early behaviour of some radical reactions, and sulfur-containing impurities can interfere with particular catalysts. Quality control therefore selects measurements according to the polymerization mechanism, connecting the identity of an impurity with the step at which it acts. Reactive monomers may also deliberately contain a small amount of inhibitor for storage, with the use process designed to handle it appropriately.
Stoichiometry can strongly limit chain length in ideal bifunctional step-growth polymerization. Imagine two kinds of building block, each carrying two connectors of its own kind, with only unlike connectors able to join. If one kind is scarce, the other eventually lacks partners and many chains remain finite. Driving the reaction further reduces the number of available unreacted pairs, but cannot create the missing type of functional group. Polyester and polyamide manufacture therefore requires attention both to how far the reaction proceeds and to whether the incoming functional-group equivalents match.
| Symbol | Meaning | Unit |
|---|---|---|
| NA,0, NB,0 | Initial counts of A and B functional groups, with A the less abundant type;0 denotes initial | count |
| r | Initial functional-group ratio of the less abundant to the more abundant type | 1 |
| p | Fraction of the less abundant A groups reacted | 1 |
| Xn | Number-average degree of polymerization, defined here as initial monomer count divided by final molecule count; n denotes number average | 1 |
| ≤ | Less than or equal to | 1 |
Reading the relationshipEach monomer has two groups of one type, so initial molecule count is half the total group count. Each intermolecular A–B link reduces molecule count by one, and pN_A,0 such reactions occur. Dividing initial count by remaining count gives the expression.
A worked exampleAt r=0.98 and p=0.99, X_n=1.98/(1.98−1.9404)=50. At r=1 with the same p=0.99, X_n=100.
ConditionsIdeal bifunctional AA+BB step growth, with only A–B reaction and no cyclization, branching, degradation or monofunctional capping. Paired diacid–diol repeat units use a corresponding different count.
For a functional-group ratio of 0.98, with 99% of the less abundant groups reacted, the ideal number-average degree of polymerization is about 50. With perfectly balanced groups at the same conversion it is 100. Here degree of polymerization is counted as the initial number of monomer molecules divided by the final number of molecules. A diacid and a diol together form one chemical repeat pair, so that counting convention must be distinguished from a repeat-pair count. The result shows why a small stoichiometric mismatch becomes conspicuous at high conversion. Monofunctional impurities can cap chain ends, while multifunctional components can introduce branching and networks; those compositions require corresponding extensions of the model.
Biologically derived materials provide further examples through lactic acid, its cyclic dimer lactide and the polylactide made from these building blocks. The spatial configuration of lactic acid affects lactide composition and stereochemical arrangement along the polymer, which in turn influences crystallization and thermal properties. A fermentation origin does not make every subsequent processing condition identical. Water, salts and other organic components still have to be removed from the fermentation broth. Producing a polyester with specified molecular mass and stereochemical composition connects biological production, purification, monomer preparation and polymerization into one manufacturing sequence.
Three linked questions help compare monomer routes: where do the atoms in the target molecule come from, which steps rearrange them, and at what purity and energy cost do they reach polymerization? Brief high-temperature exposure in cracking, hydrogen-chloride reuse in vinyl-chloride production, selectivity in enzymatic acrylamide manufacture and functional-group balancing before step-growth polymerization address different parts of that sequence. Understanding these connections turns a crowded product tree into a set of molecular changes that can be examined individually. Material names then connect to structures and manufacturing decisions rather than remaining isolated labels.
Consider: why does reducing single-pass conversion not necessarily increase fresh feed by the same proportion?
Single-pass conversion determines how much of the reaction-section feed leaves unreacted after one pass. If that material can be separated and recovered, it returns to the reaction section, increasing internal circulation and the associated equipment duty. At an ideal steady state without losses or side reactions, fresh feed replaces only the amount converted into product. Real processes also compensate for separation losses, purge flows and side-reaction consumption. Fresh feed, recycle flow, selectivity and recovery therefore need to be examined together.